Extra Questions for Class 7 Maths Chapter 10: Operations with Integers – HOTS

Fresh HOTS practice questions for Class 7 Maths Chapter 10 “Operations with Integers”, testing multiplication, division, and real-world integer applications with new numbers. These Class 7 Mathematics Chapter 10 important questions are handy for last-minute exam practice.

Q1.

Find the value of (−15) × (−4) ÷ 6.

Answer: (−15)×(−4)=60; 60÷6=10

Q2.

A submarine descends at a rate of 12 m per minute. If it starts at sea level (0 m), what is its position after 8 minutes?

Answer: Position = 0 − (12×8) = −96 m (96 m below sea level)

Q3. Assertion-Reason

Assertion (A): The product of three negative integers is negative.
Reason (R): An odd number of negative factors makes the overall product negative.

Answer: Both A and R are true, and R correctly explains A.

Q4.

Find the value of x if x × (−9) = −108.

Answer: x = −108 ÷ (−9) = 12

Q5. Spot the error

A student computed (−8) × (−3) × (−2) as “positive 48”. Identify and correct the error.

Answer: This is incorrect. With three negative factors (an odd count), the result should be negative: (−8)×(−3)=24, then 24×(−2)=−48.

Q6.

A shop makes a profit of Rs. 12 per notebook sold and a loss of Rs. 3 per pen sold (due to a discount scheme). If 200 notebooks and 500 pens are sold, what is the overall profit or loss?

Answer: Profit from notebooks = 200×12=Rs.2400. Loss from pens = 500×3=Rs.1500. Net = 2400−1500 = Rs. 900 profit

Q7.

Find three consecutive integers whose product is −120.

Answer: Try three consecutive negative integers −6, −5, −4: (−6)×(−5)×(−4) = 30×(−4) = −120. So the required integers are −6, −5, −4.

Q8.

Evaluate: (−25) × (−4) − (−30) ÷ 5

Answer: Using order of operations: (−25)×(−4)=100; (−30)÷5=−6; 100−(−6)=106

Q9.

In a quiz, +5 marks are given for a correct answer and −3 for a wrong one. A student attempted all 20 questions and scored 44. How many were correct?

Answer: Let c = correct, (20−c) = wrong. 5c − 3(20−c) = 44 → 5c−60+3c=44 → 8c=104 → c=13 correct answers

Q10.

Arrange in increasing order: (−6)×(−7), (−6)+(−7), 6−(−7), 6×(−7)

Answer: Values: 42, −13, 13, −42. Increasing order: 6×(−7) < (−6)+(−7) < 6−(−7) < (−6)×(−7) (i.e., −42 < −13 < 13 < 42)

See also: NCERT Solutions for Class 7 Maths Chapter 10

Revision Notes: Revision Notes for Class 7 Maths Chapter 10

Written by Satish

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