Extra practice questions for Class 11 Maths Chapter 8 (Sequences and Series), beyond the textbook. These Class 11 Maths Chapter 8 important questions are handy for last-minute exam practice.
Very Short Answer Questions (1 mark)
Q1. Find the common ratio of the GP: 3, 6, 12, 24.
Ans: r = 6/3 = 2.
Q2. Find the 5th term of the GP with a=2, r=3.
Ans: a₅ = 2(3)⁴ = 2(81) = 162.
Q3. Find the sum of the first 5 natural numbers using the formula.
Ans: 5(6)/2 = 15.
Q4. Find the geometric mean of 4 and 16.
Ans: √(4×16) = √64 = 8.
Q5. Does the infinite GP with r=2 have a finite sum?
Ans: No, since |r|=2 is not less than 1.
Short Answer Questions (2–3 marks)
Q6. Find the sum of the infinite GP: 1, 1/2, 1/4, 1/8, …
Ans: a=1, r=1/2 (|r|<1). S∞ = a/(1−r) = 1/(1−0.5) = 1/0.5 = 2.
Q7. Find the arithmetic mean and geometric mean of 9 and 16, and verify that AM ≥ GM.
Ans: AM = (9+16)/2 = 12.5. GM = √(9×16) = √144 = 12. Since 12.5 > 12, AM ≥ GM is confirmed.
Q8. A GP has first term 5 and common ratio 3. Find the sum of the first 4 terms using the sum formula.
Ans: S₄ = a(r⁴−1)/(r−1) = 5(3⁴−1)/(3−1) = 5(81−1)/2 = 5(80)/2 = 200.
Higher-Order Thinking / Application Questions
Q9. A ball is dropped from a height of 10 m, and after each bounce it rises to 3/5 of its previous height. Using the concept of an infinite GP, find the total distance the ball travels (theoretically, until it stops bouncing), accounting for both falling and rising distances.
Ans: The ball falls 10 m initially. Then it bounces up and down repeatedly, each time to 3/5 of the previous height, forming a GP with a=10×(3/5)=6 (first bounce height) and r=3/5, but each bounce height is travelled twice (up and down), except we count the initial fall once. Total distance = 10 (initial fall) + 2 × [sum of infinite GP with a=6, r=3/5] = 10 + 2 × [6/(1−0.6)] = 10 + 2 × 15 = 10 + 30 = 40 m.
Q10. Explain why the formula for the sum of an infinite GP, S∞ = a/(1−r), only works when |r| < 1, using the finite sum formula as a starting point.
Ans: The finite sum formula is Sn = a(1−rn)/(1−r). As n approaches infinity, the term rn approaches 0 only if |r| < 1 (since a fraction raised to higher and higher powers shrinks toward zero). If |r| ≥ 1, rn either stays constant (r=1), grows without bound (r>1), or oscillates without settling (r≤−1), so the sum does not converge to a finite value, and the infinite sum formula does not apply.
Class 11 Maths Chapter 8 – Solutions and Notes
For complete step-by-step answers and a quick summary, check the Class 11 Maths Chapter 8 Solutions and Class 11 Maths Chapter 8 Revision Notes.
See also: Chapter 2 | Chapter 3 | Chapter 4 | Chapter 5 | Chapter 6 | Chapter 7 | Chapter 8
Practice more: Chapter 2 | Chapter 3 | Chapter 4 | Chapter 5 | Chapter 6 | Chapter 7
Quick revision: Chapter 2 | Chapter 3 | Chapter 4 | Chapter 5 | Chapter 6 | Chapter 7
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- Chapter 6: Permutations and Combinations – Extra Questions with Answers
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