Class 11 Maths Chapter 3 Trigonometric Functions – Extra Questions with Answers

Switching between degrees and radians is the first skill this chapter demands, and these questions build from there into quadrant signs and standard trigonometric identities.

Last Updated: September 23, 2026

How to Approach the HOTS Questions in Trigonometric Functions

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HOTS questions on this chapter often require combining two or three identities in sequence rather than applying just one — practice chaining compound-angle and double-angle formulas together instead of expecting a single-step solution. Questions on general solutions of trig equations are also a common HOTS source — be precise about which identity you use to reduce the equation to a standard form before writing the general solution.

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Very Short Answer Questions (1 mark)

Q1. Convert 60° to radians.
Ans: 60 × π/180 = π/3.

Q2. What is the value of sin 90°?
Ans: 1.

Q3. In which quadrant is tanθ positive but sinθ negative?
Ans: Quadrant III.

Q4. State the identity relating sec²θ and tan²θ.
Ans: sec²θ = 1 + tan²θ.

Q5. What is the radian measure equivalent to 180°?
Ans: π.

Short Answer Questions (2–3 marks)

Q6. Prove that sin(90°+θ) = cosθ using the sum formula.
Ans: sin(90+θ) = sin90 cosθ + cos90 sinθ = (1)(cosθ) + (0)(sinθ) = cosθ.

Q7. Find the value of cos 75° using the sum formula, expressing 75° as 45°+30°.
Ans: cos(45+30) = cos45 cos30 − sin45 sin30 = (√2/2)(√3/2) − (√2/2)(1/2) = (√6−√2)/4.

Q8. A wheel of radius 21 cm rotates through an angle of 60°. Find the length of the arc traced (using arc length = radius × angle in radians).
Ans: 60° = π/3 radians. Arc length = 21 × π/3 = 7π ≈ 22 cm.

Higher-Order Thinking / Application Questions

Q9. Explain why radian measure, rather than degree measure, is preferred in advanced mathematics (like calculus), using the arc length formula as part of your reasoning.
Ans: In radian measure, the arc length formula simplifies to s = rθ directly, without any conversion constant, because radians are defined based on the ratio of arc length to radius. This natural relationship makes calculus formulas involving trigonometric functions (like derivatives of sin and cos) much simpler in radians than they would be in degrees, which require extra conversion factors.

Q10. Find the general solution of the equation 2sinθ = 1, and explain why trigonometric equations typically have infinitely many solutions.
Ans: sinθ = 1/2 gives θ = 30° = π/6 as a principal solution. The general solution is θ = nπ + (−1)n(π/6), for any integer n. Trigonometric equations have infinitely many solutions because trigonometric functions are periodic (sin repeats every 2π), so if one value of θ satisfies the equation, adding any multiple of the period (with the appropriate symmetry adjustments) gives another valid solution.

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More Class 11 Mathematics Extra Questions -- Chapter-wise:

Frequently Asked Questions

How would you find the value of sin 75 degrees using the sum formula?
Write 75 as 45 plus 30, then sin75 = sin45cos30 + cos45sin30, which works out to (root6 + root2) divided by 4.

If a wheel of radius 14 cm rotates through an angle of 60 degrees, what arc length does a point on its rim travel?
Convert 60 degrees to radians as pi over 3, then use arc length = radius times angle in radians, giving about 14.67 cm.

Chapter Quiz — Test Your Understanding

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