Class 9 Mathematics Chapter 4 Exploring Algebraic Identities – Extra Questions with Answers

Expanding an expression like (x+5) squared becomes fast once you recognise the underlying identity, and these questions cover expansion, factorisation and mental-math shortcuts built on that idea.

Last Updated: September 23, 2026

Very Short Answer Questions (1 mark)

Q1. Expand (x + 5)² using the identity.
Ans: x² + 10x + 25.

Q2. Factorise x² − 16 using the difference of squares identity.
Ans: (x + 4)(x − 4).

Q3. Expand (a − 3)².
Ans: a² − 6a + 9.

Q4. State the identity used to expand (x + 2)(x + 5).
Ans: (x + a)(x + b) = x² + (a+b)x + ab.

Q5. Write the identity for a³ + b³ in factored form.
Ans: a³ + b³ = (a + b)(a² − ab + b²).

Short Answer Questions (2–3 marks)

Q6. Use a suitable identity to evaluate 998² without direct multiplication.
Ans: 998² = (1000 − 2)² = 1000² − 2×1000×2 + 2² = 1000000 − 4000 + 4 = 996004.

Q7. Factorise 4x² − 9y² using an identity, showing your working.
Ans: 4x² − 9y² = (2x)² − (3y)² = (2x + 3y)(2x − 3y), using the difference of squares identity.

Q8. Expand (2x + 3y)² using the standard identity, showing the substitution.
Ans: Using (a+b)² = a²+2ab+b² with a=2x, b=3y: (2x+3y)² = (2x)² + 2(2x)(3y) + (3y)² = 4x² + 12xy + 9y².

Higher-Order Thinking / Application Questions

Q9. If a + b = 10 and ab = 21, find the value of a² + b² without finding a and b individually.
Ans: Using (a+b)² = a² + 2ab + b²: 10² = a² + 2(21) + b², so 100 = a² + b² + 42, giving a² + b² = 58.

Q10. A square garden of side (x + 4) metres has a square flower bed of side x metres removed from one corner. Using algebraic identities, find a simplified expression for the remaining garden area.
Ans: Total area = (x+4)² = x² + 8x + 16 (using the identity). Flower bed area = x². Remaining area = (x² + 8x + 16) − x² = 8x + 16 = 8(x + 2) square metres.

Square garden of side x+4 with a square flower bed of side x removed from one corner, leaving an L-shaped remaining area

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Frequently Asked Questions

How can the identity for the square of a sum be used to quickly calculate 105 squared without direct multiplication?
Writing 105 as 100 plus 5 and applying the identity gives 100 squared plus twice 100 times 5 plus 5 squared, which simplifies to 10000 plus 1000 plus 25, giving 11025 without direct multiplication.

What is the difference between the identity for the square of a sum and the identity for the difference of two squares?
The square of a sum identity expands an expression, while the difference of two squares identity factors an expression into a product, serving opposite purposes of expanding versus factorising.

Chapter Quiz — Test Your Understanding

Question 1 of 0 · Score: 0

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