Practice questions beyond the textbook exercises, testing deeper understanding of ratio and proportion for Class 8 Maths Chapter 7: Proportional Reasoning-1. These Class 8 Mathematics Chapter 7 important questions are handy for last-minute exam practice.
Extra Questions: Class 8 Maths Chapter 7 Proportional Reasoning-1
- 1 (Assertion-Reason). Assertion: 6:9 and 10:15 are in proportion. Reason: Both ratios simplify to 2:3.
Solution: Both true, and the reason correctly explains the assertion — 6:9 = 2:3 and 10:15 = 2:3, so the two ratios are equal. - 2 (Numerical). A car covers 180 km in 3 hours. At the same speed, how far will it travel in 5 hours?
Solution: Speed = 180÷3 = 60 km/h. Distance in 5 hours = 60×5 = 300 km. - 3 (Short Answer). Are the ratios 5:8 and 8:5 the same?
Solution: No — order matters in a ratio. 5:8 and 8:5 are reciprocals of each other and represent different comparisons, not the same relationship. - 4 (Applied). Two numbers are in the ratio 3:4, and their sum is 84. Find the numbers.
Solution: Total parts = 3+4 = 7; each part = 84÷7 = 12. The numbers are 36 and 48. - 5 (Assertion-Reason). Assertion: If a:b = c:d, then a:c = b:d also holds. Reason: This follows because a:b=c:d means ad=bc, which is the same condition needed for a:c=b:d.
Solution: Both true, and the reason correctly explains the assertion — both proportions reduce to the same cross-product equation, ad=bc. - 6 (Numerical). A recipe needs flour and sugar in the ratio 5:2 to make a 350 g mix. Find the quantity of each.
Solution: Total parts = 7; each part = 350÷7 = 50 g. Flour = 250 g, Sugar = 100 g. - 7 (Synthesis). If a:b = 2:3 and b:c = 4:5, find a:b:c.
Solution: Make b common: a:b = 2:3 = 8:12, and b:c = 4:5 = 12:15. So a:b:c = 8:12:15. - 8 (Applied). A map has a scale of 1:50,000. Two towns are 8 cm apart on the map. Find the actual distance in km.
Solution: 8×50,000 = 4,00,000 cm = 4,000 m = 4 km. - 9 (Short Answer). Why must both terms of a ratio be in the same unit before simplifying it?
Solution: A ratio compares two quantities as pure numbers. If the units differ (e.g. 2 m to 50 cm), they must first be converted to a common unit (2 m = 200 cm) before the ratio (200:50 = 4:1) is meaningful. - 10 (Assertion-Reason). Assertion: Dividing ₹600 in the ratio 1:2:3 gives ₹100, ₹200, and ₹300. Reason: The parts must add up to the total, and since 1+2+3=6 parts, each part = ₹600÷6 = ₹100.
Solution: Both true, and the reason correctly explains the assertion — 1×100=100, 2×100=200, 3×100=300, and these sum to ₹600.
Class 8 Mathematics Chapter 7 – Solutions and Notes
For complete step-by-step answers and a quick summary, check the Class 8 Mathematics Chapter 7 Solutions and Class 8 Mathematics Chapter 7 Revision Notes.
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More Class 8 Mathematics Extra Questions -- Chapter-wise:
- Chapter 1: A Square and A Cube
- Chapter 2: Power Play
- Chapter 3: A Story of Numbers
- Chapter 4: Quadrilaterals
- Chapter 5: Number Play
- Chapter 6: We Distribute, Yet Things Multiply
- Chapter 8: Fractions in Disguise (Percentages) - HOTS
- Chapter 9: The Baudhayana-Pythagoras Theorem - HOTS
- Chapter 10: Proportional Reasoning 2 - HOTS
- Chapter 11: Exploring Some Geometric Themes - HOTS
- Chapter 12: Tales by Dots and Lines - HOTS
- Chapter 13: Algebra Play - HOTS
- Chapter 14: Area - HOTS

